Results 1 to 1 of 1
Like Tree1Likes
  • 1 Post By mis nazma

Class 11 – Chemistry Chapter 9: SOLUTIONS

This is a discussion on Class 11 – Chemistry Chapter 9: SOLUTIONS within the 11th forums, part of the Classes category; Class 11 – Chemistry Chapter 9: SOLUTIONS Define and explain the following: a. Molarity: “The number of moles of the ...

  1. #1
    Special Member mis nazma's Avatar
    Join Date
    Jan 2013
    Location
    Pakistan
    Posts
    390
    Blog Entries
    1

    Class 11 – Chemistry Chapter 9: SOLUTIONS


    Class 11 – Chemistry

    Chapter 9: SOLUTIONS
    Define and explain the following:

    a.
    Molarity:
    “The number of moles of the solute dissolved in one liter of solution is called the molarity of the solution”.
    M = moles of solute * 1 / voL of solution in liter

    b. Molality:
    “The number of moles of the solute dissolved in one kg (1000g) of the solvent is called the molality of the solution”.
    M = mol of solute * 1/mass of solvent in kg

    c. Mole fraction:
    “The ratio of number of moles of a particular components to the total number of moles of all of the components of the solution is known as the mole fraction of that particular component”.

    d. Percentage composition by volume and weight

    Percentage composition:
    “The number of parts of the solute present in 100 parts of the solution is called percentage composition of the solution”.

    Mass by mass percentage:
    “The number of grams of the solute dissolved in 100g of the solution is called the mass percentage of the solution”.

    Volume by mass percentage:
    “The number of milliliters of the solute dissolved in 100g of the solvent is called the volume by mass percentage of the solution”.

    Volume by volume percentage:
    “The number of milliliters of the solute dissolved in 100 Mlof the solution is called the volume by volume percentage of the solution”.

    e. Fractional distillation:
    “Distillation is the process of vaporizing a liquid, condensing the vapors, and collecting the condensed vapors in a different container”.

    f. Solubility:
    “Solubility is the number of grams of the solute dissolved in 100g of the solvent at a specific temperature”.
    Solubility = (mass of solute/mass of solvent) * 100

    Factors affecting solubility:
    i. Nature of the solvent
    ii. Nature of the solute
    iii. Temperature
    iv. Pressure

    g. Colligative properties:
    “Colligative property is a property of solution which depends on the number of solute particles but nor on their nature.”
    Examples:
    1. Lowering of vapor pressure
    2. Elevation of boiling point
    3. Depression of freezing point
    4. Osmotic pressure

    h. Hydration and hydrolysis:

    Hydration:
    “Solvation is a process in which solvent molecules surround and interact with solute ions or molecules. If water is used as solvent than solvation is called hydration”.

    Hydrolysis:
    “Reaction with a solvent involving the breakdown of one or more bonds in the reacting solute is called solvolysis, if water is the solvent then the reaction is called hydrolysis”.

    www.ittaleem.com
    Attached Files Attached Files
    Mahum Hussain likes this.

Similar Threads

  1. Replies: 0
    Last Post: 12th June 2013, 09:33 PM
  2. Replies: 0
    Last Post: 3rd June 2013, 10:53 PM
  3. Replies: 0
    Last Post: 3rd June 2013, 10:48 PM
  4. Chemistry Notes Chapter 1 for Class 9
    By ahti in forum Courses
    Replies: 0
    Last Post: 22nd April 2013, 07:09 PM
  5. FSC LEVEL CHEMISTRY chapter: SOLUTIONS
    By mis nazma in forum Classes
    Replies: 1
    Last Post: 16th January 2013, 06:39 PM

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •